First we derive the powerseries for asin(x)
. Define two matrix-valued functions:
Since the UL element of nm(1,n) is the nth term ratio of atan(x) and the UR = the first term, nm(1,0) nm(1,1) nm(1,2) ... computes atan(x). Series-comparing the first five matrices with the claimed infinite product:
(The UL 0 on the LHS is really
.) But [km,nm] are a path-invariant pair:
By induction on k and n, truth on the general unit square implies truth on any infinite rectangle. The two edges at infinity degenerate, and
(series-testing the RHS:)
is another series for atan(x). Now suppose
Then
and changing variables in the km matrix:
So, dividing out the radiculus,
Testing the first five matrix terms,
Now we need merely integrate dy. But the matrix product is linear only in the UR. We can concentrate y there with a k-dependent "similarity" matrix:
Note that m(0) is the identity, and
The m(k) telescope out of the k product, and we can integrate dy:
We can restore this to canonical form with the "similarity" matrix
Since m(1) ≠ identity, we must take care on the left:
(ignoring an extant 0 times a nascent ∞). QED/2.
The [km,nm] pair (d1) we just exploited is a special and limiting case of the four dimensional system
Test path-invariance in the i-j, j-k, k-n, and n-i planes:
Given path-invariance, we are free to recoordinatize, replacing each matrix by the appropriate product of itself, the others, and their inverses:
km is too wide, but not after we specialize i and j to 1/2 (losing two dimensions and the im and jm matrices), and shift n and k by -1/2:
The (archaically named) split function "similarity" transforms all matrices ...
... while preserving path invariance:
Now the product,
which computes the sum
equals the product
This is exctly 3/2 times our asin2 identity with y=1/2
QED.
Addendum: To derive the original atan(x) (d1) pair from the gaussfed0 system, we rename variables (introducing the arbitrary offset a) and discard the im and jm matrices, leaving i and j as free parameters:
Then we contrive the "similarity" matrix that puts x in the UR of nm:
Then we shift k and specialize i and j:
Finally, let a →∞ and put in normal form:
which is where we came in. --rwg